(u+4)^2=2u^2-u+36

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Solution for (u+4)^2=2u^2-u+36 equation: 



(u+4)^2=2u^2-u+36

We move all terms to the left:

(u+4)^2-(2u^2-u+36)=0

We get rid of parentheses

-2u^2+(u+4)^2+u-36=0

We add all the numbers together, and all the variables

-2u^2+u+(u+4)^2-36=0

We move all terms containing u to the left, all other terms to the right

-2u^2+u+(u+4)^2=36

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